Amdocs Coding Question | Range of Positive Numbers

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Range of Positive Numbers

Given a range of positive numbers where 'rFrom' is the lower and 'rTo' is the upper bound, return a list that contains all the numbers in the range that are dividable by the sum of their sum.

For Example:

rFrom=10

rTo=20

The function will return 

10,12,18,20

Explanation:

10/(1+0)=10

12/(1+2)=4

Example :-

• Input:
  • 10
  • 20
• Output:
  • 10,12,18,20

Explanation:-

10/(1+0)=10  , 12/(1+2)=4 etc

Code in Python

# Code in Python
class TestImpl:
    def range(self, rFrom, rTo):
        for i in range(rFrom, rTo + 1):
            temp = i
            sum = 0
            while (temp != 0):
                r = temp % 10
                sum += r;
                temp = int(temp / 10)
            if (i % sum == 0):
                print(i, end=' ')

obj = TestImpl()
obj.range(10, 20)

"""
OUTPUT
10 12 18 20 
"""

Code in Java

import java.util.Scanner;

class Range {

    static void range(int rFrom,int rTo) {
        int sum,temp,r;
        for (int i = rFrom; i <= rTo; i++) {
            temp=i;
            sum=0;
            while(temp!=0)
            {
                r=temp%10;
                sum+=r;
                temp/=10;
            }
            if(i%sum==0)
                System.out.print(i+" ");
        }        
    }

    public static void main(String[] args) {
        range(10, 20);
    }
}
/*
OUTPUT
10 12 18 20
 */

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